condition counter results

[LetsMakeMoney]

I want to know how many times a stock has had a high that was 2% or more greater then the open. Here's my code:

def condition = if ((high - open)/open)*100 >= 2 then 1 else 0;
def counter = if condition == 1 then counter[1] + 1 else counter[1];

When I run this script on ANF, for example, I get a count of 163. But my chart is on a Monthly timeframe, the range is 8 years, so there's only 96 bars on the chart. Not understanding this counter result.

 

[LetsMakeMoney]

I want to know how many times a stock has had a high that was 2% or more greater then the open. Here's my code:

def condition = if ((high - open)/open)*100 >= 2 then 1 else 0;
def counter = if condition == 1 then counter[1] + 1 else counter[1];

When I run this script on ANF, for example, I get a count of 163. But my chart is on a Monthly timeframe, the range is 8 years, so there's only 96 bars on the chart. Not understanding this counter result.

Running BarNumber() gives me the right number of bars (96). Since there's only one monthly high per month, how can there be a result that's greater then 96? Do I have to code something to make sure the counter starts off at 0?

 

[LetsMakeMoney]

Running BarNumber() gives me the right number of bars (96). Since there's only one monthly high per month, how can there be a result that's greater then 96? Do I have to code something to make sure the counter starts off at 0?

This worked, hard setting the counter to 0. Now the result is 86.
def condition = if ((high - open)/open)*100 >= 2 then 1 else 0;
def counter = if BarNumber() == 1 then 0 else if condition == 1 then counter[1] + 1 else counter[1];

 

[halcyonguy]

how did you know what count you had? you didn't post any output code.
next time, post the whole code. don't post partial code.

good catch on setting counter to 0 at bar #1. i like to always do that.
i don't have an answer on why you see different numbers.

condition is 1 or 0, so you can use if condition then, don't need ==1

below is a better way, just in case a condition can exist on bar #1
this includes a bubble that shows the % and counter. if changes color when a condition exists.
if you list all the 'else if' lines separate, then it is easier to disable one of them and try something else.

def na = double.nan;
def bn = barnumber();

def per = round(((high - open)/open)*100,2);
input per_level = 2.0;
def condition = if per >= per_level then 1 else 0;

def counter =
 if bn == 1 and !condition then 0
 else if bn == 1 and condition then 1
 else if condition then counter[1] + 1
 else counter[1];

addlabel(1, counter, color.yellow);

addchartbubble(1, low, 
per + " %\n" +
counter
, (if condition then color.yellow else color.gray), no);
#